Mistake Master

Volumes with Cross Sections: Squares and Rectangles AB & BC

A solid sliced perpendicular to an axis has volume $\int_a^b A(x)\,dx$, where $A(x)$ is the area of one cross section: an area times a thickness is a volume. The shape of the slice comes from the problem and its base length comes from the region, as $s = y_{\text{top}} - y_{\text{bottom}}$, which is 8.4's integrand reused. Taking $s$ from a single curve assumes the lower boundary is the axis, which is true in most introductory examples and false in general; checking $s$ at one interior point and at the ends, where it should vanish, catches it.

For square cross sections $A = s^{2}$, so the base between $y = x$ and $y = x^{2}$ on $[0, 1]$ gives $V = \int_0^1 (x - x^{2})^{2}\,dx = \frac{1}{30}$. Failing to square gives $\frac{1}{6}$, the area of the base, and squaring the terms separately gives $\frac{2}{15}$ by way of the false identity $(a - b)^{2} = a^{2} - b^{2}$. A rectangle whose height is $k$ times its base has $A = k s^{2}$, while one of fixed height $3$ has $A = 3s$. Every remaining topic in the unit is this same integral with a different $A$, discs and washers included.

THE SEGMENT ON THE LEFT IS THE SIDE OF THE SQUARE ON THE RIGHT. THE BASE REGION ONE SLICE EACH SLICE IS A SQUARE STANDING ON THE BASE ITS SIDE IS THE GAP BETWEEN THE CURVES: s = x − x² ONE SLICE HAS AREA s² AND THICKNESS dx AT x = 0.5 THE REGION RUNS FROM 0.25 TO 0.5, SO s = 0.25. THE SIDE VANISHES AT BOTH ENDS, WHERE THE TWO CURVES MEET.
Drawn to scale at $200$ px per unit horizontally and $140$ px per unit vertically on the left panel, with the parabola computed rather than sketched. The marked segment sits at $x = 0.5$ and has length $0.25$; the square on the right is drawn in oblique projection, so its two visible sides are equal in the solid.
EVERY CROSS SECTION IN THIS UNIT, WITH s THE BASE LENGTH. THE SHAPE AREA OF ONE SLICE SQUARE, SIDE s RECTANGLE, HEIGHT k TIMES s k s² RECTANGLE, FIXED HEIGHT h h s ISOSCELES RIGHT △, LEG s s² / 2 EQUILATERAL △, SIDE s (√3 / 4) s² SEMICIRCLE, DIAMETER s (π / 8) s² ONLY ROW THREE IS LINEAR IN s. READ THE SENTENCE FOR WHICH ONE.
Rows one to three belong to this topic and rows four to six to 8.8, but the method never changes: find $s$ from the region, then look up the shape. The third row is the only one where the height does not come from the region, so it is the only one that is not quadratic in $s$.

The work

3 ways in · any order
Lesson
Volumes with Cross Sections: Squares and Rectangles

Builds a volume as the integral of one slice's area, measures the side as the distance between the region's two boundaries rather than off a single curve, squares the whole difference rather than its terms, distinguishes a rectangle of proportional height from one of fixed height, and frames the next five topics as the same integral with a different slice.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on square and rectangular cross sections: reading the side as a distance between two boundaries, applying the area formula correctly, avoiding the false expansion of a squared difference, and setting up slices perpendicular to the right axis.

Not yet available · 10 items
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.

Take the diagnostic to identify your misconceptions