Determining Limits Using Algebraic Manipulation AB & BC
A $\frac{0}{0}$ form at $x = a$ means numerator and denominator share a factor of $(x-a)$. Cancelling it yields an expression that agrees with the original everywhere except at $a$ itself, which is enough, because a limit never consults the point. Factoring handles polynomials, multiplying by a conjugate handles radicals, and combining over a common denominator handles complex fractions. After each rewrite, substitute again and reclassify.
Three things go wrong. Substitution gets reported without classification, so an unfinished $\frac{0}{0}$ becomes a final answer. The indeterminate form gets read as a value or as proof the limit fails. And cancellation is applied to a term rather than a factor, as in simplifying $\frac{x^2+3x}{x}$ to $x^2+3$, which produces an expression not equal to the original and therefore a wrong limit rather than an unsimplified one. Sign errors from reversed factors such as $3-x$ against $x-3$ are the common arithmetic slip.
The work
3 ways in · any order
Lesson
Determining Limits Using Algebraic Manipulation
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Why cancelling a common factor preserves a limit, the factors-not-terms rule that keeps it valid, and the three standard rewrites: factoring, conjugates, and common denominators.
Diagnostic
10-item topic check
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Ten items spanning the three failure modes of this topic: substituting without classifying, misreading an indeterminate form, and cancelling a term instead of a factor. Take it cold to find which one is yours, or after the lesson to confirm it is not.
Targeted Practice
Drill a single misconception
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Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.