Mistake Master

Exponential Models with Differential Equations AB & BC

Every proportional-rate model solves to $y = y_{0}e^{kt}$, and the constant carries the behaviour: positive $k$ grows, negative $k$ decays, and the units of $k$ are one over time, so it is neither an amount per unit time nor a duration. Doubling time and half-life come from setting the final value to a multiple of the initial one, which cancels $y_{0}$ and leaves $t = \frac{\ln 2}{k}$ in size; a half-life of $5730$ years gives $k \approx -1.21 \times 10^{-4}$ per year, and after $n$ half-lives the fraction left is $\left(\frac{1}{2}\right)^{n}$.

Newton's law of cooling, $\frac{dT}{dt} = k(T - T_{a})$, produces a SHIFTED exponential: the difference from the surroundings decays, not the temperature itself, so $T = T_{a} + Ce^{kt}$ with $C = T_{0} - T_{a}$. Dividing by $T - T_{a}$ to separate discards the constant solution $T = T_{a}$, which this family happens to recover at $C = 0$. The same shape covers any quantity approaching a limit $L$: $y = L + Ce^{kt}$, with $y = L$ as its equilibrium.

TWO MODELS, ONE EQUATION: dy/dt = ky WITH k = ±0.2 AND y(0) = 100. GROWTH, k = +0.2 DECAY, k = −0.2 t = 3.47 FOR BOTH 0 5 10 DOUBLING TIME AND HALF-LIFE ARE BOTH ln 2 DIVIDED BY THE SIZE OF k.
Drawn to scale at $40$ px per unit of time across and $0.25$ px per unit of quantity up. The two marked points sit at the same instant, $t = \frac{\ln 2}{0.2} \approx 3.47$, where the upper curve has reached $200$ and the lower one $50$.
NEWTON COOLING, AND THE SOLUTION THE DIVISION REMOVES dT/dt = k(T − 70) k IS NEGATIVE dT/(T − 70) = k dt LEGAL ONLY IF T ≠ 70 ln|T − 70| = kt + C ONE CONSTANT, HERE T − 70 = Ce^(kt) THE DIFFERENCE DECAYS T = 70 + Ce^(kt) C = 0 GIVES T = 70 THE LOST CONSTANT SOLUTION COMES BACK IN THE LAST LINE, AT C = 0. DECAYING T ITSELF GIVES COFFEE COLDER THAN THE ROOM AROUND IT. AT t = 0 THE CONSTANT IS C = T₀ − 70, POSITIVE OR NEGATIVE. ANY LIMIT L WORKS THE SAME WAY: y = L + Ce^(kt), EQUILIBRIUM y = L.
The second line is where a solution disappears and the fifth is where it returns. Checking the discarded case takes three seconds and it is not always this forgiving; some families never recover what the division threw away.

The work

3 ways in · any order
Lesson
Exponential Models with Differential Equations

Solves the proportional-rate equation once and reads everything off the constant: sign for growth or decay, units that rule out the two common misreadings, and a logarithm for half-life and doubling time. Then builds the shifted exponential of Newton's law of cooling and locates the ambient value as the equilibrium the separation removes.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on exponential models: the sign and meaning of the growth constant, half-life and doubling time computed with a logarithm rather than a division, the shifted exponential for a quantity approaching a limit, and the constant solution that dividing to separate discards.

Not yet available · 10 items
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.

Take the diagnostic to identify your misconceptions