Mistake Master

Finding Taylor Polynomial Approximations of Functions BC only

The $n$th-degree Taylor polynomial centred at $a$ is $\sum_{k=0}^{n} \frac{f^{(k)}(a)}{k!}(x-a)^{k}$, where the derivative is evaluated at the centre to give a number, the factorial cancels the one produced by differentiating $(x-a)^{k}$ down to a constant, and the power matches the order. Differentiating $P_n$ $k$ times and setting $x = a$ leaves exactly $f^{(k)}(a)$, which is what the factorial is for, so omitting it makes that derivative $k!$ times too large. The coefficient fails in two distinct ways: the factorial goes missing, or the derivative order is paired with a mismatched power, and the rule is that order, factorial and exponent are the same number in every term.

The centre is part of the object rather than a detail, so a polynomial built from $f^{(k)}(0)$ while written in powers of $(x-1)$ has halves referring to different points, and writing $x^{k}$ for $(x-a)^{k}$ is correct only in the Maclaurin case $a = 0$, whose tidiness is what disguises the general form. Two Taylor polynomials of one function at different centres are different polynomials agreeing with $f$ in different places, and neither is more correct. Drawn together, $\cos x$, $P_2$ and $P_4$ meet at the centre and separate as $|x|$ grows, with $P_4$ tracking the curve visibly longer: at $x = 2.5$ the values are $-0.8011$, $-0.4974$ and $-2.1250$. For $\cos x$ the odd derivatives vanish at $0$, so $P_2$ and $P_3$ are the same polynomial.

cos x WITH ITS DEGREE 2 AND DEGREE 4 POLYNOMIALS AT x = 0. cos x P4, DEGREE 4 P2, DEGREE 2 ALL THREE MEET AT THE CENTRE AND SEPARATE AS |x| GROWS A HIGHER DEGREE BUYS A WIDER MATCH, NOT A PERFECT ONE.
Drawn to scale at $72$ px per unit horizontally and $45$ px per unit vertically, all three curves computed at $21$ points from $x = -2.5$ to $x = 2.5$. They agree exactly at the marked centre; by $x = 2.5$ the values are $\cos 2.5 \approx -0.8011$, $P_4 \approx -0.4974$ and $P_2 = -2.1250$, so the degree-$4$ polynomial is still close while the degree-$2$ one has left entirely.
BUILDING THE POLYNOMIAL FOR e^x AT a = 0. k f^(k)(0) k! THE TERM WITHOUT THE k! 0 1 1 1 1 1 1 1 x x 2 1 2 x²/2 x², TWICE TOO BIG 3 1 6 x³/6 x³, SIX TIMES 5 1 120 x^5/120 x^5, 120 TIMES k, THE FACTORIAL AND THE EXPONENT ARE ALWAYS THE SAME NUMBER.
The last column shows the factorial omission growing with the degree: harmless-looking at $k = 1$, wrong by a factor of $120$ by $k = 5$. Since every derivative of $e^{x}$ is $1$ at the centre, this table isolates the factorial as the only thing distinguishing a correct term from an incorrect one.

The work

3 ways in · any order
Lesson
Finding Taylor Polynomial Approximations of Functions

Builds the Taylor coefficient from the derivative order and the factorial and shows what each contributes, separates the factorial omission from the mismatched-order error, and establishes that the centre is part of the object rather than a detail, with an overlay of the cosine curve and two of its polynomials on one set of axes.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on Taylor polynomials: assembling the coefficient with the right derivative order and the right factorial, keeping the exponent matched to both, building about the requested centre, and reading what a polynomial approximation does and does not promise.

Not yet available · 10 items
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.

Take the diagnostic to identify your misconceptions