Riemann Sums, Summation Notation, and Definite Integral Notation AB & BC
Sigma notation packs a sum into four parts: an index that counts, a lower bound where the count starts, an inclusive upper bound where it stops, and a term evaluated at each value. A sum from $i = 2$ to $i = 5$ has four terms, since terms are one more than gaps. A Riemann sum on $[a, b]$ with $n$ equal pieces is $\sum_{i=1}^{n} f(x_i)\Delta x$ with $\Delta x = \frac{b-a}{n}$ and $x_i = a + i\Delta x$, so on $[1, 3]$ it reads $\sum_{i=1}^{n} f\!\left(1 + \frac{2i}{n}\right)\frac{2}{n}$, where the same $\frac{2}{n}$ is both the width of a rectangle and the spacing of the samples.
Letting $n \to \infty$ turns the sum into $\int_{a}^{b} f(x)\,dx$, and reading a given limit backwards is a match on three items: the factor playing $\Delta x$ gives the length of the interval, the constant sitting beside the $i$ term gives $a$, and the rest is $f$. The resulting symbol denotes a number. Its variable is a dummy, so $\int_{0}^{2} f(x)dx$ and $\int_{0}^{2} f(t)dt$ are equal; its limits are inputs to $f$ rather than values of $f$; and the $dx$ names the variable and carries the width that gives the answer its units.
The work
3 ways in · any order
Lesson
Riemann Sums, Summation Notation, and Definite Integral Notation
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Names the four parts of a sigma expression and counts its terms, builds the general Riemann sum with the sample point assembled from the left endpoint and the index, takes the limit to reach the integral sign, and then reads the symbol backwards: matching a given limit to its interval, and separating the dummy variable, the limits of integration and the differential.
Diagnostic
10-item topic check
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Ten items spanning the two failure modes of this topic: misreading sigma or integral notation, including index bounds, the dummy variable and the role of the differential, and building a sum with the wrong width, sample points or number of terms.
Targeted Practice
Drill a single misconception
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Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.