Mistake Master

Integrating Using Substitution AB & BC

Substitution reverses the chain rule. Set $u$ to the inside of a composition whose derivative appears as a factor, compute $du$, and rewrite so that no $x$ survives; if one does, the substitution has not fitted and continuing produces an expression in two variables. A missing constant factor can be supplied, since constants pass through an integral, so $\int x(x^{2}+1)^{4}dx = \frac{1}{2}\int u^{4}du$. A missing variable factor cannot: moving a $\frac{1}{2x}$ across the integral sign is not a legal step, and $\int (x^{2}+1)^{4}dx$ is simply a different problem.

With limits attached there are exactly two correct finishes. Convert each $x$-limit through $u$ and evaluate entirely in $u$, or return to $x$ first and use the original limits. Doing both, or neither, is the error, and doing neither is the silent one: evaluating $\left[\frac{u^{5}}{5}\right]$ at $x = 0$ and $x = 2$ instead of at $u = 1$ and $u = 5$ gives $6.4$ rather than $624.8$, an ordinary-looking number with nothing visibly wrong. Converted limits need not increase, and swapping them to make them do so negates the result.

SUBSTITUTION IS THE CHAIN RULE RUN BACKWARDS. ∫ 2x(x² + 1)^5 dx u = x² + 1, du = 2x dx ∫ u^5 du ANTIDIFFERENTIATE IN u u^6/6 + C PUT x BACK (x² + 1)^6/6 + C EVERY x MUST GO. A LEFTOVER x MEANS THE SUBSTITUTION DID NOT FIT. dx IS REPLACED BY du, NOT SIMPLY DELETED. AN INDEFINITE ANSWER IS NOT DONE UNTIL x IS BACK.
Each arrow is a step you can check on its own. The right-hand column lists what goes wrong at that step, in the same order.
∫ FROM 0 TO 2 OF 2x(x²+1)^4 dx, WITH u = x² + 1. THE x LINE x = 0 x = 2 PUSH EACH LIMIT THROUGH u u = 1 u = 5 CONVERTED, THE INTEGRAL IS ∫ FROM 1 TO 5 OF u^4 du = 624.8. EVALUATING THAT AT 0 AND 2 INSTEAD GIVES 6.4 AND LOOKS FINE.
The two lines carry the same interval measured in different variables. Nothing on the page marks which set of numbers an antiderivative in $u$ is waiting for, which is why the wrong pair produces a plausible answer.

The work

3 ways in · any order
Lesson
Integrating Using Substitution

Runs substitution as five checkable steps and insists that no original variable survives the rewrite, separates a missing constant factor from a missing variable factor, then handles definite integrals with the two legal routes, converting the limits or converting back, and shows the wrong-number-that-looks-right produced by doing neither.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items spanning the two failure modes of this topic: a differential that does not match, leaving a stray variable or an unaccounted constant, and limits of integration left in the original variable while the antiderivative is written in the new one.

Not yet available · 10 items
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and moves you to the next.

Take the diagnostic to identify your misconceptions