Mistake Master

Circular Motion

▶︎  Watch it animatedinteractive step-through · ~3 min · optional

In circular motion the velocity is always changing, because its direction turns even when its speed does not. That change is an acceleration pointing to the center, the centripetal acceleration ac = v²/r. By Newton’s second law something must supply the matching inward force, and the radial forces add up to ΣFr = m·v²/r. When the speed is steady, that radial force is the whole net force; when the speed also changes, a tangential force acts alongside it. That force is never a new kind of force. It is the role played by whatever real force already acts: the tension in a string, gravity on a satellite, the normal force from a track, the friction under a turning car.

UNIFORM CIRCULAR MOTION · NET FORCE POINTS INWARD center v Fnet = m·v2/r ac = v2/r (inward, never zero) ONE INWARD FORCE, FROM A REAL FORCE · NO OUTWARD FORCE · CONSTANT SPEED STILL ACCELERATES
The ball moves at a steady speed, yet its velocity arrow keeps swinging to a new direction, so it is always accelerating inward. There is one net force, pointing to the center, equal to m·v²/r. No outward force acts, and the acceleration is not zero just because the speed is constant.
Spin the Puck · Open the sandbox →

Three pictures get drawn wrong. Sketching centripetal force as a separate arrow, an extra force beside the real ones, when the inward force is one of those real forces, not a second one. Inventing an outward centrifugal force in the ground frame, when no outward force acts on an object rounding a curve — the feeling of being flung outward is inertia, not a force. And reading constant speed as zero acceleration, when the speed can hold steady while the velocity's direction keeps turning, so the acceleration is v²/r inward and never zero.

The work

3 ways in · any order
Lesson
Circular Motion

How circular motion always has an inward acceleration v²/r even at constant speed, why the centripetal force is the role of a real force rather than a separate arrow, and why there is no outward force in the ground frame. Worked examples find a centripetal acceleration, a vertical-loop minimum speed, and a banked-curve angle. Closes with a ten-scenario skill check on all three traps.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on the main mistakes for Topic 2.10: drawing centripetal force as a separate arrow, inventing an outward centrifugal force, and reading constant speed as zero acceleration. Take it cold to find what is shaky, or after the lesson to confirm it is not.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the mistakes you've missed and drill it on its own. The round is adaptive: two correct in a row clears it and you move on.

Take the diagnostic to identify your misconceptions