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Valence electrons and ionic compounds

Valence electrons decide how an atom bonds. When a metal hands electrons to a nonmetal, both become charged ions that snap together — and the formula that results is set by one rule: the charges must balance.

§1

Valence electrons decide the chemistry.

Only the outermost electrons — the valence electrons — take part in ordinary bonding. Their count, which for a main-group element matches its group, sets what ions an atom tends to form.

Many main-group atoms gain or lose valence electrons to reach the electron count of the nearest noble gas — a stable, filled-shell arrangement. Metals on the left have few valence electrons and tend to lose them, becoming positive cations; nonmetals on the right are a few electrons short and tend to gain them, becoming negative anions. This "noble-gas-like" pattern is a reliable guide for the main group, but it is a trend, not a universal law — transition metals and some other ions settle on charges that do not leave a simple noble-gas configuration.

When a metal hands electrons to a nonmetal, the resulting cations and anions attract each other and lock into an ionic compound. What matters for the formula is not the noble-gas story but the charges themselves: the compound must come out electrically neutral.

UNIT 1 TOPIC 1.8 • VALENCE ELECTRONS AND IONIC COMPOUNDS TRANSFER, THEN BALANCE ELECTRON TRANSFER Na 1 valence e⁻ Cl 7 valence e⁻ transfers 1 e⁻ Na⁺ Cl⁻ NaCl (1 : 1) FORMULA FROM CHARGE BALANCE Al³⁺ O²⁻ 2 of Al 3 of O Al₂O₃ 2(+3) + 3(−2) = 0 → neutral WHAT HOLDS THE LATTICE: COULOMBIC ATTRACTION Attraction ∝ (charge of cation × charge of anion) ÷ distance between ions. Higher charges or smaller ions → stronger lattice → higher melting point. MgO (2+, 2−) is held far more strongly than NaCl (1+, 1−) — and melts far hotter. AP Chemistry · Unit 1 · Atomic Structure & Properties
Fig. 1.8.1 A metal transfers valence electrons to a nonmetal, producing a cation and an anion. The compound's formula is whatever makes the total charge zero: Al³⁺ and O²⁻ combine as Al₂O₃, since 2(+3) + 3(−2) = 0. The oppositely charged ions are then held in a lattice by Coulombic attraction — stronger for higher charges and smaller ions.
§2

Building an ionic formula.

A neutral compound has no leftover charge. That single requirement fixes the formula — you just balance the pluses against the minuses.

  1. Find each ion's charge. For main-group elements, the common charge follows the group: group 1 forms 1+, group 2 forms 2+, group 16 forms 2−, group 17 forms 1−, and so on.
  2. Combine so the charges cancel. Take enough of each ion that the total positive charge equals the total negative charge. The compound as a whole must be neutral.
  3. Read the counts as subscripts. The number of each ion needed becomes its subscript. A quick shortcut: the magnitude of one ion's charge becomes the other ion's subscript (the "criss-cross"), then reduce to the simplest ratio.
  4. Check neutrality and simplify. Confirm the charges sum to zero, and reduce subscripts to their smallest whole-number ratio (Ca²⁺ with O²⁻ is CaO, not Ca₂O₂).

Notice the formula comes entirely from charge balance, not from atoms "sharing" or "completing octets." The octet idea helps predict a main-group ion's charge; neutrality is what turns those charges into a formula.

§3

The pieces you'll meet.

Quick reference card. Charge is the currency; neutrality is the rule.

valence
Valence electrons
Outer-shell electrons that bond. For main-group atoms, the count matches the group.
+
Cation
Positive ion from losing electrons. Metals, on the left, form these.
Anion
Negative ion from gaining electrons. Nonmetals, on the right, form these.
net 0
Charge neutrality
The rule that sets the formula: total positive charge must equal total negative charge.
lattice
Coulombic lattice
Oppositely charged ions held in a 3-D array. Stronger for higher charges and smaller ions.
group
Group → charge (main group)
1→1+, 2→2+, 16→2−, 17→1−. A trend, not a rule for transition metals.
§4

Worked example: the formula of aluminum oxide.

Question. Aluminum (group 13) and oxygen (group 16) form an ionic compound. What is its formula?

Step 1 — find the charges. Aluminum loses 3 valence electrons to form Al³⁺. Oxygen gains 2 to form O²⁻.

Step 2 — balance the charges. The charges (+3 and −2) don't cancel one-to-one. The least common multiple is 6: you need two Al³⁺ (giving +6) and three O²⁻ (giving −6).

Step 3 — write the subscripts. Two aluminums and three oxygens gives Al2O3. (Shortcut: criss-cross the charge magnitudes — the 2 from oxygen and the 3 from aluminum — to the opposite subscripts.)

Step 4 — check neutrality. 2(+3) + 3(−2) = +6 − 6 = 0. Neutral, and already in the simplest ratio. ✓

Sanity check. Nothing about "octets" told us the subscripts — the +3 and −2 charges did. If you'd guessed AlO by pairing them one-to-one, the charge would be +1 left over, which no neutral compound can have.

§5

3 mistakes that cost real points.

Pitfall · 01

"Every ion ends up with a full noble-gas shell."

That's a solid guide for main-group ions — sodium to Na⁺, oxygen to O²⁻ — but it isn't universal. Transition metals commonly form more than one ion (iron as Fe²⁺ or Fe³⁺), and plenty of stable ions don't land on a tidy noble-gas configuration. Treating "reach an octet" as an absolute law leads to wrong charges outside the main group.

Fix. Use the noble-gas pattern to predict main-group ion charges. For transition metals, take the charge as given (often from a Roman numeral) rather than forcing an octet.

Pitfall · 02

"Just write the two elements side by side."

Aluminum and oxygen is not "AlO." The formula is whatever makes the charges cancel, and +3 with −2 needs a 2:3 ratio — Al2O3. Pairing ions one-to-one only works when their charges are equal in size. Skipping the charge balance produces formulas that aren't neutral and can't exist.

Fix. Always balance the total + against the total −. Criss-cross the charge magnitudes to subscripts, then reduce to the simplest ratio.

Pitfall · 03

"All ionic compounds are held together about equally."

The strength of an ionic lattice follows Coulomb's law: it grows with the product of the ion charges and shrinks with the distance between ions. Magnesium oxide (2+ with 2−) is bound far more strongly than sodium chloride (1+ with 1−), which is why MgO melts near 2850 °C and NaCl near 800 °C. Ignoring charge and ion size hides these large differences.

Fix. Compare lattices by charge first, then size: higher charges and smaller ions mean a stronger lattice and a higher melting point.

§6

Skill Check.

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