Constructing a Confidence Interval for the Difference Between Two Population Means
▶︎ Watch it animatedinteractive step-through · ~3 min · optionalA two-sample t interval is $(\bar{x}_1 - \bar{x}_2) \pm t^{*}\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}$. For method A ($\bar{x}_1 = 78.4$, $s_1 = 8.1$, $n_1 = 30$) against method B ($\bar{x}_2 = 71.2$, $s_2 = 9.6$, $n_2 = 28$): the difference is 7.2, $SE \approx 2.341$, and with the conservative $df = 27$ and $t^{*} = 2.052$ the interval is $7.2 \pm 4.80$, or about $(2.40, 12.00)$ points. The conditions are random, independence between groups, the 10% condition per group, and a shape check per group.
The standard error gets built by subtracting variances or adding standard errors instead of adding variances. The degrees of freedom get set to $n_1 + n_2 - 2$ from memory rather than to technology's value or the conservative $\min(n_1, n_2) - 1$. The shape condition gets checked once for the combined data or only for the larger group, when a 28-observation group below the guideline needs its own plot. And the interpretation drops the word difference, the order of subtraction, or both populations, leaving a sentence a reader cannot act on.
The work
3 ways in · any order
Lesson
Constructing a Confidence Interval for the Difference Between Two Population Means
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Builds the two-sample t interval with a standard error that adds each group's variance, chooses degrees of freedom between technology's value and the conservative rule, checks the 10% and shape conditions once per group, and writes an interpretation naming both populations and the order of subtraction.
Diagnostic
10-item topic check
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Ten items on two-sample intervals for means: standard errors combined wrong, degrees of freedom taken as n1 plus n2 minus 2, shape checked only for the larger group, and interpretations missing the word difference. Take it cold to find your habit, or after the lesson to check it is gone.
Targeted Practice
Drill a single misconception
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Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears it for now and moves you to the next. Two in a row is a checkpoint, not proof: if the error resurfaces later, the misconception comes back.