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Introduction to Probability

▶︎  Watch it animatedinteractive step-through · ~3 min · optional

A random process generates outcomes that fill a sample space, and an event is a subset of it. Two dice generate 36 equally likely ordered outcomes, so the event sum at least 10 has probability $\frac{6}{36}$, while the eleven possible sums are events of very different sizes and are not equally likely. Every probability satisfies $0 \le P(A) \le 1$ and the whole sample space sums to 1, which makes both a check on any answer. The complement rule $P(A^c) = 1 - P(A)$ follows, and it is the standard route through at least one questions: with four independent parts each failing at 0.2, $P(\text{at least one}) = 1 - (0.8)^4 = 0.5904$.

Three failures recur. Probabilities are reported outside 0 to 1, or a set of outcome probabilities is left summing to something other than 1, with no check performed. Equally likely is assumed from the mere number of outcomes: two outcomes read as 50-50, three read as a third each, when the count of outcomes says only how many pieces exist, not their sizes. And at least one is computed by adding the individual probabilities, $4 \times 0.2 = 0.8$ instead of $1 - 0.8^4$, which double counts the overlaps and, with enough trials, produces an answer greater than 1.

sample space: 36 equally likely ordered rolls 1 2 3 4 5 6 6 5 4 3 2 1 shaded: sum is 10 or more 6 of 36 outcomes, P = 1/6 the eleven SUMS are events, not the sample space, and they hold 1 to 6 cells each sum 7 fills a diagonal of 6; sum 2 fills a single cell
Count over the outcomes the process generates. The eleven sums look like a sample space and are not one: they are events of wildly unequal size.
4 parts, each fails with probability 0.2 at least one fails: 0.5904 none: 0.4096 1 - (0.8)^4 = 1 - 0.4096 = 0.5904 adding instead: 4 x 0.2 = 0.8 at 10 parts the same addition gives 2.0, which no probability can be
The complement turns four calculations into one. Adding the individual failure probabilities counts the overlapping ways twice and eventually breaks the 0-to-1 rule outright.

The work

3 ways in · any order
Lesson
Introduction to Probability

Sets up sample spaces and events, the two rules every probability obeys, when outcomes may be treated as equally likely and when that is an unearned assumption, and the complement rule as the route through at least one.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on probability foundations: answers outside 0 to 1, distributions that do not sum to 1, two outcomes assumed to be 50-50, at least one computed by adding, and short runs read as verdicts. Take it cold to find your habit, or after the lesson to check it is gone.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears it for now and moves you to the next. Two in a row is a checkpoint, not proof: if the error resurfaces later, the misconception comes back.

Take the diagnostic to identify your misconceptions