Mistake Master
Parametrizing implicit curves
Topic 4.5 gave curves as solution sets; Topic 4.1 gave curves as journeys. This topic connects them: given an implicit equation, build a parametric function that travels its curve. The two disciplines that make it honest: verify by substitution that the journey stays on the curve, and audit the coverage, because staying on the curve is not the same as covering it.
§1
The verification move.
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A proposed parametrization $(x(t), y(t))$ belongs to an implicit curve exactly when substituting both formulas into the equation produces a true statement for every t. For the circle $x^2 + y^2 = 9$, try $x = 3\cos t$, $y = 3\sin t$: substitution gives $9\cos^2 t + 9\sin^2 t = 9(\cos^2 t + \sin^2 t) = 9$. True for all t, so every traced point sits on the circle.
The Pythagorean identity $\cos^2 t + \sin^2 t = 1$ is the engine of every circular and elliptical parametrization, but it only fires when the coefficients cooperate. Check by substituting, never by resemblance: plenty of cos/sin pairs that look right produce $4\cos^2 t + 9\sin^2 t$, which is not constant and belongs to no circle.
§2
The standard covers.
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- Circle $x^2 + y^2 = r^2$: use $x = r\cos t$, $y = r\sin t$ on $[0, 2\pi]$. Starts at (r, 0), sweeps counterclockwise.
- Ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$: use $x = a\cos t$, $y = b\sin t$. Each coefficient is the square root of its own denominator, matched to its own axis; substitution then collapses to $\cos^2 t + \sin^2 t = 1$.
- A function's graph $y = f(x)$: use $x = t$, $y = f(t)$. Trivial and perfectly legal; every explicit graph is one substitution away from parametric form.
- A line segment from P to Q: interpolate, $x$ and $y$ each running linearly from their P value to their Q value as t goes 0 to 1.
These are templates, not laws: they are the most convenient covers, chosen among infinitely many.
§3
Coverage: on the curve is not all of the curve.
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Substitution proves the journey stays on the curve. It says nothing about how much of the curve gets visited: that is the t interval's job, and it must be audited separately. $x = \cos t, y = \sin t$ on $[0, \pi]$ satisfies $x^2 + y^2 = 1$ at every instant and covers only the top half.
Coverage can also fail through the formulas themselves. $x = t^2, y = t^4$ satisfies $y = x^2$ for every real t, but $t^2 \ge 0$ traps x in the right half: no interval choice ever reaches the parabola's left arm. The audit question is concrete: what set of x values (and y values) do the formulas actually produce over the interval? Match that against the piece you were asked to cover.
§4
Many covers, all valid.
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An implicit curve never has just one parametrization. The unit circle is covered by $(\cos t, \sin t)$ counterclockwise, by $(\cos t, -\sin t)$ clockwise, by $(\cos 2t, \sin 2t)$ at double speed (a full loop in t-length $\pi$), and by versions starting anywhere on the rim. All substitute correctly; they differ in start, speed, and direction, which is precisely what parametrization adds to an implicit curve.
So treat "find a parametrization" as an engineering task with many right answers, and "is this parametrization correct" as two checks in sequence: substitute (does it stay on the curve?), then audit (does it cover the requested piece, in the requested manner?).
§5
Skill Check.
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Ten scenarios. Pick the chips that match your answer, then check. A scenario marks complete the first time every part is right. Progress saves on this device.