Displacement, Velocity, and Acceleration
▶︎ Watch it animatedinteractive step-through · ~3 min · optionalThis is where calculus enters the course. Velocity is the rate of change of position: $v(t) = dx/dt$, the slope of $x(t)$ at one instant. Acceleration is the rate of change of velocity: $a(t) = dv/dt$, the slope of $v(t)$ at one instant. Run the operations in reverse and you get integrals: $\Delta x = \int v(t)\,dt$ is the area under $v(t)$, and $\Delta v = \int a(t)\,dt$ is the area under $a(t)$. Every motion problem in mechanics passes through these four operations.
Most of the trouble comes from reading $dx/dt$ as an ordinary quotient of small numbers, or from computing $\Delta v / \Delta t$ when what was asked is $dv/dt$ at a single instant. The misconceptions in this topic drill those exact moves: confusing an average with an instantaneous rate, dropping the constant of integration, mixing up which derivative gives which extremum, and treating velocity and acceleration as one quantity instead of two independent vectors.
The work
3 ways in · any order
Lesson
Displacement, Velocity, and Acceleration
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Goes from average velocity and acceleration to their instantaneous forms ($v = dx/dt$, $a = dv/dt$) with a worked polynomial. Then the reverse: integrate from $a(t)$ to $v(t)$ to $x(t)$, with the initial condition fixing the constant each time. Closes with a ten-question skill check on the six in-scope misconceptions.
Diagnostic
10-item topic check
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Ten items across the six in-scope misconceptions: velocity-versus-acceleration mixups, slope-versus-area in calculus form, dropping the constant of integration, treating $dx/dt$ as a fraction, polynomial max-position versus max-velocity, and average-versus-instantaneous. Take it cold to see what's still tangled, or after the lesson to confirm it isn't.
Targeted Practice
Drill a single misconception
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Pick a failure mode you missed and drill it on its own. The round is adaptive: two correct in a row clears the misconception and you move on.