Mistake Master
Student view — seeing the site as a student does
CED objectives

The Photoelectric Effect

▶︎  Watch it animatedinteractive step-through · ~3 min · optional ⚙︎  Open the appletPhotoelectric Bench · separate the dial that moves K_max from the one that moves the current, then find the slope and both intercepts on the graph

The photoelectric effect gives $K_{\text{max}} = hf - \phi$, where the frequency describes the light and the work function describes the metal, and intensity appears nowhere. Emission therefore requires a minimum frequency, below which no electron leaves however bright the beam, because each electron interacts with one photon at a time. Above threshold, frequency sets the maximum kinetic energy and the stopping voltage while intensity sets how many electrons come off per second. On a plot of stopping voltage against frequency the slope is $h/e$, the vertical intercept is $-\phi/e$ and the horizontal intercept is the threshold frequency.

Four errors dominate. Treating the emission threshold as a brightness threshold, so a strong enough beam of any colour is expected to eject electrons. Treating the work function as a property of the incident beam rather than of the plate, so switching to ultraviolet is said to raise it. Letting beam intensity control the maximum kinetic energy instead of the number of electrons per second, which predicts a stopping voltage that moves with brightness. And reading the stopping-voltage graph backwards, taking the slope as the work function or the intercept as Planck's constant.

two knobs, two entirely separate effects current voltage V(stop) 2× intensity 1× intensity SAME frequency, different brightness: the plateau lifts, V(stop) does NOT move V(stop) larger V(stop) SAME brightness, higher frequency: V(stop) moves out, the plateau does not
Each panel changes exactly one knob. The feature that responds is different in each, which is precisely what a wave picture could not deliver.
V(stop) = (h/e) f − φ/e: match it to y = mx + b V(stop) f f₀ = φ/h −φ/e metal 2 slope = h/e a UNIVERSAL constant: the same for every plate intercepts carry the metal so a new plate slides the line without tilting it taking the slope as φ, or the vertical intercept as h, gets both halves backwards
The two lines are parallel, and that is the point: one feature of this graph belongs to nature and the other two belong to the sample.

The work

3 ways in · any order
Lesson
The Photoelectric Effect

Makes the emission threshold a frequency threshold, assigns the work function to the plate, splits the frequency and intensity knobs, and reads the stopping-voltage graph off its own rearranged equation.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items spanning the failure modes of this topic: treating the threshold as a brightness threshold, giving the work function to the beam, raising the electron energy with intensity, and reading the stopping-voltage graph backwards. Take it cold to find which one is yours, or after the lesson to confirm it is not.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears it for now and moves you to the next. Two in a row is a checkpoint, not proof: if the error resurfaces later, the misconception comes back.

Take the diagnostic to identify your misconceptions