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Introduction to acids and bases

Strip acid-base chemistry to its core and it is one proton changing hands. Even pure water plays the game, quietly splitting a few of its molecules into ions.

§1

Proton donors and acceptors.

In the Brønsted-Lowry model, an acid donates a proton (H⁺) and a base accepts one. After the transfer, the acid becomes its conjugate base and the base becomes its conjugate acid.

A conjugate pair differs by exactly one proton (HA and A⁻; H₂O and OH⁻). The same substance can act as an acid or a base depending on its partner — water is amphoteric.

Water autoionizes: a tiny fraction of water molecules transfer a proton, giving equal H⁺ and OH⁻. At 25 °C, Kw = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴. This sets the neutral baseline for the pH scale.

UNIT 8 TOPIC 8.1 • INTRODUCTION TO ACIDS AND BASES CONJUGATE PAIRS Proton transfer creates conjugate acid–base pairs that differ by exactly one H⁺. BRØNSTED–LOWRY ACID — donates a proton (H⁺), the H⁺ donor BASE — accepts a proton (H⁺), the H⁺ acceptor acid base conjugate base conjugate acid HA + B A⁻ + BH⁺ H⁺ transfers One proton moves from the acid to the base — giving two conjugate pairs. CONJUGATE PAIR 1 HA / A⁻ HA loses H⁺ to become A⁻. The acid and its conjugate base. Differ by exactly one proton (H⁺). CONJUGATE PAIR 2 B / BH⁺ B gains H⁺ to become BH⁺. The base and its conjugate acid. Differ by exactly one proton (H⁺). CED ANCHOR A conjugate acid–base pair differs by exactly one H⁺. Whichever way the reaction runs, HA/A⁻ and B/BH⁺ stay linked by proton transfer. AP Chemistry · Unit 8 · Acids and Bases
Fig. 8.1.1 A Brønsted-Lowry acid donates a proton (becoming its conjugate base) and a base accepts one (becoming its conjugate acid). Water autoionizes, so even pure water has equal H⁺ and OH⁻ (Kw = 1.0 × 10⁻¹⁴ at 25 °C).
§2

Following the proton.

Track the H⁺ to name every role.

  1. Find the proton donor. The species that loses an H⁺ is the acid.
  2. Find the proton acceptor. The species that gains an H⁺ is the base.
  3. Name the conjugates. Acid minus H⁺ is its conjugate base; base plus H⁺ is its conjugate acid.
  4. Remember autoionization. Water self-ionizes to equal H⁺ and OH⁻, with Kw = 1.0 × 10⁻¹⁴ at 25 °C.
§3

The pieces you'll meet.

Proton transfer, plus water's own equilibrium.

acid
Acid (Brønsted)
A proton (H⁺) donor.
base
Base (Brønsted)
A proton (H⁺) acceptor.
conjugate
Conjugate pair
Two species differing by one proton.
amphoteric
Amphoteric
Can act as acid or base (e.g. water).
autoionization
Autoionization
Water self-ionizes to equal H⁺ and OH⁻.
Kw
Kw
[H⁺][OH⁻] = 1.0 × 10⁻¹⁴ at 25 °C.
§4

Worked example: ammonia in water.

Reaction. NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.

Base. NH₃ accepts a proton, so it is the base; it becomes NH₄⁺, its conjugate acid.

Acid. H₂O donates a proton here, so it acts as the acid; it becomes OH⁻, its conjugate base.

Autoionization. Separately, pure water always has a small equal amount of H⁺ and OH⁻ from self-ionization, fixing Kw = 1.0 × 10⁻¹⁴ — the reference for a neutral solution.

§5

Mistakes that cost real points.

Pitfall · 01

"A base must contain OH."

A Brønsted base is any proton acceptor, not only hydroxide-containing species. Ammonia is a base because it accepts a proton, despite having no OH. Defining a base by OH misses many bases.

Fix. Identify a base as a proton acceptor; check whether it gains an H⁺, not whether it contains OH.

Pitfall · 02

"Pure water contains no ions."

Water autoionizes, so even pure water contains a small, equal amount of H⁺ and OH⁻ (each 1.0 × 10⁻⁷ M at 25 °C). It is not completely un-ionized; that autoionization is what makes water neutral, not ion-free.

Fix. Remember pure water has a tiny equal concentration of H⁺ and OH⁻ from autoionization (Kw = 1.0 × 10⁻¹⁴).

Pitfall · 03

"A substance is fixed as either an acid or a base."

Roles depend on the partner. Water donates a proton (acts as an acid) to ammonia but accepts one (acts as a base) from HCl. Amphoteric species switch roles, so you cannot fix a label in advance.

Fix. Determine acid or base per reaction by following the proton, not by a fixed label.

§6

Skill Check.

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