Mistake Master
Free body diagrams
Every dynamics problem starts the same way: pick one object, list every force on it, draw each force as an arrow from a single point. That picture is the free body diagram. Build it right and Newton's second law does the rest. Build it wrong and no algebra will save you.
§1
What a free body diagram actually is.
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A free body diagram (FBD) is a stripped-down picture: one object, every force on it drawn as an arrow. Two rules drive it.
The object becomes a dot. No wheels, no shape, no detail. The dot stands for the object's center of mass, and that single point is enough.
Only forces acting on that object appear. Forces the object pushes on other things (the floor, the rope, the next cart) belong on someone else's diagram. This is where most FBD mistakes start: a busy scene tempts you to draw every arrow you see, even arrows that don't belong.
The point of all this stripping-down is to make Newton's second law, $\vec{F}_{net} = m\vec{a}$, easy to use. You can't add forces until you know what they are and where they point. The FBD tells you that.
§2
A four-step procedure.
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Use this procedure for every FBD. Go slowly the first dozen times; speed comes later. Most wrong answers come from skipping Step 1 or Step 3.
- Pick the object. Choose one object (or one group of things that move together). If two boxes are tied together by a rope, you usually need two FBDs, one for each box.
- Replace the object with a dot. Drop the picture of the block, the cart, the planet. Put a dot in its place. The dot stands for the object's center of mass. That's all the geometry you need.
- List every force on the object. Two questions, in order. First: does anything touch it? Each contact gives a normal force, maybe friction, maybe tension. Second: is it near a planet? If yes, gravity acts. If you can't name what's causing a force, that force isn't real and doesn't go on the diagram.
- Draw each force as an arrow from the dot, and label it. Tail at the dot, head pointing the way the force pushes or pulls. Label each arrow with a symbol ($F_g$, $F_N$, $F_T$, etc.). Direction matters; getting the lengths to match is nice but not required yet.
Notice what's not on the list. There's no step for "draw an arrow for where the object is moving." Velocity is not a force and never goes on an FBD. There's no step for "split into components," either. That comes later, after the FBD is built, when you set up the algebra.
§3
The forces you'll meet.
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Six forces cover almost every problem in AP Physics 1. Each one has a symbol, a direction rule, and a color used consistently in this lesson (and in the Skill Check below).
Quick test for whether a force belongs: name what's causing it. Gravity? Earth. Normal force? A specific surface. Tension? A specific rope. If you can't name a real, external cause, the force isn't real. Imaginary forces wreck more FBDs than anything else. (More on that in §6.)
§4
Worked example: block on a flat table.
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Setup. A 3 kg block sits at rest on a smooth flat table. Build its FBD.
Step 1. The object is the block. Not the table, not the block plus table. Just the block.
Step 2. Replace the block with a dot.
Step 3. Anything touching the block? Yes, the table on the bottom. The table pushes up perpendicular to its surface (normal force). Friction? Only if the block tends to slip. Nothing is pushing it sideways, so no tendency to slip, so no friction. Near a planet? Yes, so gravity acts down. Two forces total.
Step 4. Two arrows from the dot: $F_g$ down, $F_N$ up.
Notice how little the FBD says about the table. From the block's point of view, the table is just the source of one upward push. Whatever else the table is doing (pressing on the floor, holding up a lamp, sitting in a kitchen) doesn't show up here, because none of it acts on the block.
Also notice what's not drawn. There's no arrow for the block pushing down on the table. That force is real, but it acts on the table, not on the block. The FBD shows only forces on the block. Mixing the two up is the most common mistake on this kind of problem (more on it in §6).
§5
Worked example: block on a rough incline.
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Setup. A 5 kg block sits on a ramp tilted 30° above horizontal. The ramp is just rough enough to keep the block from slipping. Build the block's FBD.
Step 1. The object is the block.
Step 2. Replace it with a dot.
Step 3. Anything touching the block? Yes, the ramp surface underneath. The ramp pushes perpendicular to its surface (normal force), pointing out of the ramp. Friction? Yes. The block tends to slide down (gravity pulls along the slope, nothing else holds the block), so static friction points up the slope to oppose that tendency. Near a planet? Yes, so gravity acts down. Three forces total.
Step 4. Three arrows from the dot. $F_g$ straight down (toward Earth, not toward the ramp). $F_N$ perpendicular to the ramp, pointing away. $F_f$ along the ramp, pointing up the slope.
Two things to flag.
Gravity doesn't point into the ramp. It points toward Earth, which is straight down on the page, no matter how the ramp is tilted. A common slip is to draw gravity perpendicular to the ramp because the block is "on" the ramp. The ramp doesn't change the direction of gravity.
The normal force isn't equal to $mg$ on an incline. On a flat surface, $F_N = mg$ falls out of $\sum F_y = 0$. On a ramp, only the perpendicular part of gravity ($mg\cos\theta$) presses into the surface, so $F_N = mg\cos\theta$, which is less than $mg$. The takeaway: the normal force is whatever the surface gives to keep the object from sinking through. Its size depends on what else is acting, and you find it from the algebra.
§6
Three mistakes that cost real points.
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"There must be a force in the direction of motion."
A puck slides east on smooth ice. A book skids to a stop. A pendulum swings through the bottom of its arc. In each case, you might want to draw a forward arrow because the object is moving forward. Something has to be pushing it, right?
No. Velocity is not a force. By Newton's first law, an object keeps moving on its own; it doesn't need a push to keep going. The puck on smooth ice has only gravity (down) and normal (up). The book skidding to a stop has gravity, normal, and friction (backward, opposing motion). No forward arrow. The pendulum at the bottom of its swing has only gravity and tension (both vertical). The forward velocity is preserved by inertia, not by a force.
Fix. Use the agent test from §3. For every arrow, name the object causing that force. If you can't name one, don't draw the arrow.
"Components count as forces of their own."
On an incline, gravity splits into $mg\sin\theta$ along the ramp and $mg\cos\theta$ perpendicular to the ramp. Useful for algebra, but those are components of one force, not two new forces. On the FBD, draw the original gravity arrow ($F_g$, straight down). Only when you start the algebra do you replace it with its components, on a separate side sketch.
Drawing $F_g$ and $mg\sin\theta$ and $mg\cos\theta$ all on the same diagram triple-counts gravity. The AP Physics 1 rule: free-body diagrams show whole forces, not components. One force, one arrow.
Fix. One arrow per force. If a force is at an awkward angle (gravity on a ramp, a rope pulling up-and-right), draw it at that angle. Don't break it into components on the FBD. Do that on a side sketch when the algebra needs it.
"The normal force always equals $mg$."
For a block on a flat table with nothing else acting on it, $F_N = mg$ falls out of $\sum F_y = 0$. After enough flat-surface examples, students start treating that as a definition: the normal force IS the weight. It isn't. The normal force is whatever the surface gives to keep the object from sinking through. Its size depends on what else is going on.
Three quick counterexamples. Incline: on a ramp at angle $\theta$, only the perpendicular part of gravity presses the block into the ramp, so $F_N = mg\cos\theta < mg$. Rope pulled up at an angle: a crate dragged by a rope angled $25°$ above horizontal gets a partial lift, so the floor only needs $F_N = mg - F\sin25° < mg$. Push from above: a stick pressed at $25°$ below horizontal pushes the crate into the floor, so $F_N = mg + F\sin25° > mg$.
Fix. Treat $F_N = mg$ as a result that sometimes pops out of the perpendicular equation, not as a starting fact. The FBD doesn't lock in a size for $F_N$. The algebra does that, separately, and the answer changes case by case.
§7
Skill Check.
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Ten scenarios. For each one, pick a direction for every force that's there and "Not present" for every force that isn't. The diagram updates live. Check your answer when you're ready. A scenario marks complete the first time every force is right. Progress saves on this device.