Mistake Master
Home Unit 2 · Exponential and Logarithmic Functions 2.1·2.2·2.3·2.4·2.5·2.6·2.7·2.8·2.9·2.10·2.11·2.12·2.13·2.14·2.15 Lesson
Skill Check 0 / 10 complete

Modeling with logarithmic functions

A logarithmic model is the exponential story run backward: instead of equal input steps producing equal output factors, equal input factors produce equal output steps. This topic teaches you to spot that signature in data and context, to read the parameters of $f(x) = a + b\log(x)$ without swapping their jobs, and to demand more evidence than one lucky point before calling a model validated.

§1

The log signature: factors in, amounts out.

An exponential function turns equal input steps into equal output factors. A logarithmic function is its mirror image: equal input factors produce equal output steps. If multiplying x by 10 always adds the same amount to the output, whether x went from 1 to 10 or from 100 to 1000, you are looking at a log.

Check a table for it the same way you check ratios for an exponential, just with the roles swapped. Inputs 1, 10, 100, 1000 with outputs 5, 8, 11, 14: each tenfold jump in x adds exactly 3 to y. That is the signature. Equal input steps adding equal amounts would be linear; equal input steps multiplying the output would be exponential. Equal input factors adding equal amounts is logarithmic, and nothing else does that.

§2

Reading a + b log(x) without swapping the jobs.

The workhorse form is $f(x) = a + b\log_{10}(x)$. Each parameter has one job:

  1. a is the value at x = 1, because $\log_{10}(1) = 0$ wipes out the second term. Not the value at x = 0: the model is not even defined there.
  2. b is the amount added per factor of 10 in x. Multiply x by 10 and the log rises by exactly 1, so the output rises by exactly b. It is a per-factor step, never a per-unit slope and never a percent growth rate.

To fit the form to data, anchor a at the x = 1 reading, then count factor-of-10 jumps: if f rises from 5 at x = 1 to 11 at x = 100, that is two factors of 10, so $2b = 6$ and b = 3. The single most common error in this topic is reading b as "the amount f grows per unit of x." A log model has no such number: its per-unit growth shrinks continuously, which is exactly why the per-factor step is the parameter worth naming.

§3

Log scales in the wild.

Several famous measurement scales are logarithms wearing uniforms: pH, decibels, and Richter magnitude all report the log of an underlying quantity. On every one of them, a step on the scale is a factor underneath. One pH unit is a factor of 10 in hydrogen ion concentration, so pH 4 water carries not twice but $10^2 = 100$ times the concentration of pH 6 water (and lower pH means more acidic). Ten decibels is a factor of 10 in sound intensity. One Richter unit is a factor of 10 in ground motion amplitude.

The trap is reading scale steps additively, as if pH 6 minus pH 4 meant "a little more of the same stuff." Whenever a scale is logarithmic, translate differences on the scale into factors underneath before saying anything quantitative. The natural log, $\ln(x)$, changes none of this: it is simply the log with base $e \approx 2.718$, so a model $g(t) = 2 + 1.5\ln(t)$ adds 1.5 per factor of e in t, and behaves like every other log model.

§4

Validation is a pattern claim, not a point claim.

A model with two free parameters can be forced through any one data point, and through any two. So "my log model passes through (10, 5)" validates nothing: it is a statement about the model's flexibility, not the data's shape. Real validation checks the whole pattern: do equal input factors add equal output amounts across the table? Do the residuals scatter without a trend when the model is subtracted off?

Shape vibes fail for the same reason. Plenty of families rise and slow down: logs, square roots, saturating exponentials. "It slows down, so it is a log" picks a family by silhouette. The discriminating question is always the signature test, because only the log adds equal amounts per equal factor. And one more habit worth keeping: a log model has no ceiling. $f(x) = 6 + 2\log_{10}(x)$ passes 8 at x = 10, 10 at x = 100, 12 at x = 1000, and keeps climbing forever, ever more slowly. Slowing is not stopping.

§5

Skill Check.

Ten scenarios. Pick the chips that match your answer, then check. A scenario marks complete the first time every part is right. Progress saves on this device.

0 of 10 scenarios complete