Mistake Master

Conservation of Linear Momentum

▶︎  Watch it animatedinteractive step-through · ~3 min · optional

A system keeps its momentum when its net external impulse is zero (or negligible over a short interval): outside forces may be absent, may cancel, or may be too brief to matter, and in every such case pbefore = pafter. In a collision the forces the objects put on each other are internal and cancel in pairs, so the total runs straight through. Kinetic energy is a separate ledger: it survives a perfectly elastic collision but drops in an inelastic one, where the objects stick and the lost energy turns to heat. A system at rest that bursts apart keeps its total at zero, so the pieces fly off with equal and opposite momenta.

MOMENTUM IS CONSERVED WHEN NO OUTSIDE IMPULSE ACTS collision: the total carries through before 3 kg 4 m/s 1 kg at rest total p = 12 kg·m/s after (stuck) 4 kg 3 m/s p = 12 still · KE 24 → 18 J from rest: equal and opposite momenta released at rest 1 kg 6 m/s 3 kg 2 m/s momentum: equal magnitude, opposite ways p = 6 p = 6 total p = 0 TOTAL MOMENTUM HOLDS · ENERGY NEED NOT · THE LIGHTER PART RECOILS FASTER
A 3 kg cart at 4 m/s striking a 1 kg cart at rest and sticking keeps the total momentum at 12 kg·m/s, now 4 kg moving at 3 m/s, while the kinetic energy falls from 24 J to 18 J. A body at rest that bursts apart sends a light piece and a heavy piece off with equal and opposite momenta that sum to zero, so the lighter piece is faster.
Conservation Explorer · Open the sandbox →

The errors here cluster around the word isolated. Students treat conservation as automatic, setting momentum-before equal to momentum-after for a system that isn't isolated — a falling ball, a sliding block, a ball off a wall — or expecting a single object to keep its own momentum, when conservation needs zero net external impulse. They botch recoil and explosions, scoring the parts by equal speeds or equal kinetic energies (or letting the total grow) instead of equal and opposite momenta that sum to the start, so the lighter part comes out faster. And they confuse the two ledgers, assuming kinetic energy is conserved in every collision or reading an inelastic energy drop as a broken law, when momentum is conserved either way and kinetic energy only in an elastic collision.

The work

3 ways in · any order
Lesson
Conservation of Linear Momentum

How a system's momentum is conserved when its net external impulse is zero, so the total before equals the total after, which makes isolated a choice of where the system boundary is drawn; why collisions conserve momentum because the contact forces are internal, while kinetic energy survives only an elastic collision and drops in an inelastic stick; how recoil and explosions from rest split into equal and opposite momenta that sum to zero, the lighter part faster; and how to keep the momentum and energy ledgers separate. Worked examples handle sticking collisions, recoil speeds, and energy-loss checks. Closes with a ten-scenario skill check on all three traps.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items on the main mistakes for Topic 4.3: treating momentum as conserved for a system that is not isolated or for a single object, mis-scoring recoil and explosions by equal speeds or equal energies instead of equal and opposite momenta, and confusing the momentum and kinetic-energy ledgers by expecting energy to be conserved in every collision. Take it cold to find what is shaky, or after the lesson to confirm it is not.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the mistakes you've missed and drill it on its own. The round is adaptive: two correct in a row clears it and you move on.

Take the diagnostic to identify your misconceptions