Mistake Master
Student view — seeing the site as a student does
CED objectives

Ampère's Law

▶︎  Watch it animatedinteractive step-through · ~3 min · optional ⚙︎  Open the appletAmperian Loop Lab · place and orient the loop, commit to the signed enclosed current and whether B factors out

Ampere's law states that the circulation of the total magnetic field around any closed path equals $\mu_0$ times the current threading it: $\oint\vec{B}\cdot d\vec{\ell} = \mu_0 I_{\text{enc}}$. It is always true, and it hands you $B$ only when symmetry makes the field constant in magnitude and everywhere tangent along the chosen loop, as it does for an infinite wire, an ideal solenoid, and a toroid. The enclosed current is a signed census: currents piercing along the right-hand thumb count positive, each turn of a coil counts separately, and inside a uniform thick conductor only the fraction $r^2/R^2$ threads the loop. A current loop in a uniform field feels zero net force and a torque $\vec{\tau} = \vec{\mu}\times\vec{B}$ with $\vec{\mu} = NIA\hat{n}$.

Four errors dominate. Erasing an outside current's field from the integrand, when what vanishes is its net circulation and not its field. Factoring $B$ out of the integral around a loop where the field varies, which turns a true statement into a false formula. Miscounting the enclosed current by adding magnitudes without signs, dropping the turn count of a solenoid, or using the full current inside a thick wire instead of the enclosed fraction. And giving a loop in a uniform field a net translational force, or putting maximum torque at the orientation where the torque is actually zero.

outside currents: field YES, net circulation NO Amperian loop I₁ enclosed I₂ outside I₂'s field reaches every point of the loop WITH it on one side, AGAINST it on the other: net zero deleting I₂'s field is the error symmetry breaks: B no longer factors out
The right-hand side of the law only ever counts what pierces the loop. The left-hand side integrates the total field, which is why a neighbor changes nothing about the equation and everything about whether it can be solved.
uniform field: forces cancel, torque does not B I F F (equal, opposite) net force zero, but the pair is a couple: it rotates the loop τ 90° 180° μ along B: zero, stable max: plane CONTAINS B
The torque curve peaks where the moment is perpendicular to the field, which is where the loop's plane contains it. The orientation students most often name as maximum, plane perpendicular to the field, is the zero.

The work

3 ways in · any order
Lesson
Ampère's Law

Separates what Ampere's law always states from the symmetry it needs to be solvable, turns the enclosed current into a signed and turn-weighted census, and settles torque on a current loop.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items spanning the failure modes of this topic: erasing an outside current's field, factoring B out of an integral with no symmetry to justify it, miscounting the enclosed current, and giving a loop in a uniform field a net force instead of a torque. Take it cold to find which one is yours, or after the lesson to confirm it is not.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears it for now and moves you to the next. Two in a row is a checkpoint, not proof: if the error resurfaces later, the misconception comes back.

Take the diagnostic to identify your misconceptions