Mistake Master
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CED objectives

Electric Fields

▶︎  Watch it animatedinteractive step-through · ~3 min · optional ⚙︎  Open the appletField Bench · traced field lines with a probe that reports its distance from the nearest one, a launched charge whose parabola crosses them, and a sphere that asks about its material first

The electric field at a point is set by the source charges around it, $\vec{E} = \vec{F}/q$, so the test charge divides out and the field belongs to the location. The force on a charge placed there is $\vec{F} = q\vec{E}$ with the sign kept, so a positive charge is pushed along the field and a negative charge opposite to it. Field lines give the direction of that push, their density carries the strength, and contributions from several sources add as vectors. In a conductor at equilibrium the excess charge sits on the surface and the interior field is zero; a charged insulator keeps charge throughout its volume and has a field inside.

Six errors dominate. Reading $E = F/q$ as though a larger probe produced a larger field. Copying the field arrow onto a negative charge instead of reversing it. Treating a field line as the path a moving charge will follow. Reporting zero field at a point that merely falls between two drawn lines. Adding or cancelling field magnitudes without drawing the two arrows, which swaps the like-charge and unlike-charge midpoints. And carrying the conductor's zero interior field over to a charged insulator, where the charge stays where it was put.

draw both arrows before adding anything + + equal POSITIVE pair: arrows oppose E = 0 at the midpoint + opposite pair: arrows agree they ADD, and the total is doubled the error swaps these two: “opposite charges, so they cancel” every arrow points AWAY from a positive source and TOWARD a negative one, which is all the rule you need
The signs of the sources decide which way each arrow points. Cancellation belongs to the like pair, not to the unlike one.
a field line is the direction of the push, never the route + launched sideways parabola the error traces the straight vertical line and calls it the path steady sideways velocity plus a steady push: same construction as a thrown ball
The field lines here are perfectly straight and the charge's path is not. Motion is built from the velocity it already has plus the push the line describes.

The work

3 ways in · any order
Lesson
Electric Fields

Divides the test charge out of the field definition, reverses the force on a negative charge, reads a field-line map without treating lines as trajectories, and superposes contributions as vectors.

Skill check · 10 scenarios
Diagnostic
10-item topic check

Ten items spanning the failure modes of this topic: making the field depend on the test charge, pushing a negative charge along the field, reading a field line as a path, calling blank space zero field, adding field magnitudes without arrows, and giving a charged insulator a conductor's empty interior. Take it cold to find which one is yours, or after the lesson to confirm it is not.

Not started · 10 items · ~15 min
Targeted Practice
Drill a single misconception

Pick one of the failure modes you missed and drill it on its own. The round is adaptive: two correct in a row clears it for now and moves you to the next. Two in a row is a checkpoint, not proof: if the error resurfaces later, the misconception comes back.

Take the diagnostic to identify your misconceptions